Looking at the chart we can plainly see that 6600 RPM is the optimalshift point in all gears. It's a good thing too. Remember we just boughta carburetor using that figure.
So now we have our hotrod with a strong motor and a matched carburetor,and we know when to shift to get the most out of the wheel torque, butwe're still not winning the races. The reason is we haven't looked at weightdistribution yet. Weight distribution is the final factor that will winor loose a race. For drag racing, the two main factors we will want toknow is center of gravity from front to rear and it's height. Ideally wewant 100% of the cars weight on the rear wheels. This is where all thetorque and acceleration is. Start with front to rear first, as that answerwill be a part of height's formula.
To find center of gravity from front to rear you need three things:A tape measure, a big scale and this formula:
F = (Rear Wheel Weight ÷ Total Weight) x Wheelbase
On our 1963 Corvette, with a wheelbase of 98", and a weight of 2859lbs,we take a reading from a scale with only the rear wheels on, and solvefor F this way:
F = (1300 ÷ 2859) x 98 = 0.455 x 98 = 44.561
The center of gravity height gets a bit more complicated in boththe setup and the math. I'll go through step by step using the chart belowas reference. First thing you need to do is set the rear of the car upon blocks, with the scale under them. For our model I have used 2ft blocks.Now take the readings again. For sake of experiment I will say the readingat the rear scale went from 1300 to 1192. Looking at the equation,
G = (Rear Scale Readings ÷ Total Scales Reading) x L
we almost have enough information to solve now. The one factor we don'thave yet is L. However we know that our blocks are 24" and our wheelbaseis 98". We can find the 3rd side of the triangle, or L, by using the Theoremof Pythagoras, which states that, in a right triangle, the square of theside opposite the right angle equals the sum of the squares of the othertwo sides. So the 98" wheelbase is the side opposite the right angle. 98squared is 9604. The other known side is 24" blocks. 24 squared is 576.The square of the third side will be 9604 minus 576 or 9028. So the measurementof the third side will be the square root of 9028, or 95.02. By using theformula to solve for G we know that G = 39.6.
Now we're ready to solve for H using the formula
H = (F ÷ TAN 0) - (G ÷ SIN 0) + R
Using a little trigonometry and our friend Chief Soh Cah Toa, we cansolve tan = 24/95 or 0.25, and sin = 24/98 or 0.24. R is a simple measurement,in our case coming out to 10.5. By substituting our numbers we get an answerof H = 23.74.
Now we are ready to take those figures with us to the tire shopand suspension garage to have them work their magic. They will be ableto match everything on your car to move the center of gravity back andeliminate tire hop and suspension squatting, and hopefully you will startwinning some races.
So go out there and have some fun with your car. Just keep inmind this last formula:
BAC = ((ounces x % alcohol x 0.075)÷Weight) - (hours x 0.015)
This paper was written as an assignment for Ian Walton's Math G -Math for liberal Arts Students - at Mission College. If you use material from this paper please acknowledge it.
HTTP://WWW.NETVETTES.COM/1963.HTML10/20/00
HTTP://WWW.PRESTAGE.COM/CARMATH/DEFAULT.ASP10/05/00
HTTP://WWW.MORTEC.COM/EXAMPLE.HTM10/05/00
Auto Math Handbook Basic Calculations, Formulas, Equations and Theoryfor Automotive Enthusiasts by John Lawlor 1991 HP Books
Practical Problems in Mathematics for Automotive Technicians Third Edditionby George Moore 1985 Delmar Publishers
How to Make Your Car Handle by Fred Puhn 1976 HP Books
Holley Carburetors by Mike Urich & Bill Fisher 1972 HP Books